In this article, we are going to solve a mathematical series with the help of a c program.
Math Equation:-
for -1< x <1
Now we are going to solve this problem by using c programming language. You have to paste the below code into your compiler and run this program. After that you get an Output or answer of the above equation.
Program:-
#define LOOP 100 #define ACCURACY 0.0001 int main(){ int n; float x, term, sum; printf("Input valude of x: "); scanf("%f",&x); sum=0; for(term=1;n=1;n<=LOOP;++n){ sum+= term; if(term<=ACCURACY) goto output; //EXIT FROM THE LOOP term*= x; } printf("\n FINAL VALUE OF N IS NOT SUFFICIENT\n"); printf("TO ACHIEVE DESIRED ACCURACY\n"); goto end; output: printf("\nEXIT FROM LOOP\n"); printf("Sum= %f; No. of terms =%d\n",sum,n); end: ; //Null statement return 0; }
OUTPUT:- Input value of x: .21 EXIT FROM LOOP Sum= 1,265800; No. of terms =7 Input value of x: .75 EXIT FROM LOOP Sum= 3.999774; No. of terms =34 FINAL VALUE OF N IS NOT SUFFICIENT TO ACHEVE DESIRED ACCURACY
You can copy this code into your compiler and run this program.
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Thanks!